Anagram_Palindrome_Check

public static boolean checkPalindrome(String input)
{
        int [] count = new int[26];
        for( int i = 0; i < input.length(); i++ )
        {
            char ch = input.charAt(i);
            count[ch-'a']++;
        }
        int oddOccur = 0;
        for( int cnt:count )
        {
            if( oddOccur > 1) // more than 1 char should have odd frequency
                return false;
            if( cnt%2 == 1 )
                oddOccur++;
        }
        return true;
}